Find three consecutive odd intergers whose sum is 219

1st odd = 71

2nd odd  = 73

3rd odd  = 75

Step-by-step explanation:

As numbers are consecutive odd so let:

1st odd = x

2nd odd = x + 2

3rd odd = x + 4

According to given condition:

x + x +2 + x + 4 = 219

Adding like terms

3x + 6 = 219

Subtracting 6 from both sides

3x + 6 -6 = 219-6

3x = 213

Dividing both sides by 3

x = 213/3

x = 71

So the numbers will be:

1st odd = x = 71

2nd odd = x + 2 = 71 + 2 = 73

3rd odd = x + 4 = 71 + 4 = 75

Proof:

1st odd + 2nd odd + 3rd odd = 219

71 + 73 + 75 = 219

219 = 219

Hence proved!

I hope it will help you!

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

answer: my brother can figure it out, imma go get him so i can answer : ) edit: my brother is sleeping, sorry man

step-by-step explanation: