Your school sells yearbooks every spring. the total profit p made depends on the amount x
the school charges for each yearbook. the profit is modeled by the equation p= -2x^2 + 70x
+ 520. what is the smallest amount in dollars the school can charge for a yearbook and
make a profit of at least $1000?

x=25.63

Step-by-step explanation:

turn p into 1000.

1000= -2x^2+70x+520

Subtract 520 from both sides

1000-520= 480

480= -2x^2+70x

Apply the quadratic formula, and x=25.63

So you have to charge at least $25.63

Step-by-step explanation:

The given expression is

Where is profit and is money.

Now, with the restriction of making profits of at least $1000, the expression would be

We need to multiply the inequality by -1/2,

Now we solve the quadratic expression

Solving with a calculator, the numbers that satisfy the quadratic expression are approximately and

The image attached shows the graph solution of this inequality.

Therefore, the smallest solution to make a profit of at least $1000 is $9.361.

answer: 230 miles ( vote ! )

step-by-step explanation:

180.39 minus 17.99 equals 162.4

then divide 162.4 by .80 to get 230