Can you answer this question as soon as possible.

The intensity of the first earthquake is 6.31 times the second one

Step-by-step explanation:

The given formulae is M=log()

Here for both the earthquakes the value of S is same.

Let the Intensity of the first earthquake be I1 and the second be I2.

Given M1=7.5

M2=6.7

Now  M1=log()------1

M2=log()-----2

Now subtract 1 and 2 we get

M1-M2=log()

I1/I2=

I1=I2(

I1=I2*6.31

step-by-step explanation:

x^2 -12x + 36 + y^2 = 36

x^2 + y^2 = 12x

r^2 = 12rcos(theta)

r = 12 cos(theta)

step-by-step explanation:

the original amount doesn't ''re just looking for the time it takes for 1/2 of the substance to we have

(1/2) =)     take the ln   of both sides

ln (1/2)   = )   and we can write

ln(1/2) = ) lne     and lne   = 1     so we have

ln(1/2) = -.1092t     divide both sides by -.1092

t = ln(1/2)/-.1092 = about 6.347 days = about 6.3 days (rounded)