Consider the binomial (u^2 − v^3)^6.
a. find the term that contains v^6.
b. find the term that contains u^6.
c. find the fifth term.

The answer to your question is:

Step-by-step explanation:

(u² - v³)⁶ = u¹² - 6(u²)⁵(v³) + 15(u²)⁴(v³)² - 20(u²)³(v³)³ + 15(u²)²(v³)⁴ - 6(u²)(v³)⁵ +

                (v³)⁶

             = u¹² - 6u¹⁰v³ + 15u⁸v⁶ - 20u⁶v⁹ + 15u⁴v¹² - 6u²v¹⁵ + v¹⁸

a.- Find the term that contains v⁶ = 15u⁸v⁶

b.- Find the term that contains u⁶ = - 20u⁶v⁹

c.- Find the fifth term = 15u⁴v¹²

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

b) well because you get well