The power p of a jet of water is jointly proportional to the cross sectional area a and to the cube ofthe velocity v. (a) write the formula for p. use lower case k as the proportionality constant. (b) if the velocity is tripled and the cross sectional area is doubled, by what factor will the power increase? enter a number. submit answer save progress

a)  

b)  54

Step-by-step explanation:

a)

If one quantity, A, is jointly proportional to other 2 quantities (B & C), we can write proportionality equation as:

Where

k is the proportionality constant

Now, for this problem, P is jointly proportional to A and CUBE OF V, so we can write:

b)

Now velocity, V, is triples, which means it becomes 3V

Also, cross sectional area, A, is doubled, which means it becomes 2A

Let's put these into formula and see the difference:

So, power is multiplied by a factor of 54. Power becomes 54 times if Area is doubled and velocity is tripled ( as seen ).

solution:

we have to construct

∠m nt ≅ ∠p qr

the steps to draw this construction are

step 1: use a compass to draw an arc from point q which intersects the side pq at point a and the side qr at point b.

step 2: draw a segment nt and use the same width of the compass to draw an arc from point n which intersects the segment nt at a point x.

step 3:

step 4: join points n and y using a straightedge.

step 3:

option (d).maintaining the same width of the compass as ab, draw an arc from point x such that it intersects the arc drawn from n in a point y.

to draw   congruent angles , 1. width of compasses while drawing two angles should be same i.e from point at which angle has to be drawn, 2.the distance between the two points where the compass intersects the two sides should be same while drawing any two congruent angles.