2. the number 1 is a zero of the polynomial p(x)=x^3−3x^2+7x−5.
a. write p(x) as a product of linear factors.
b. what are the solutions to the equation x^3−3x^2+7x−5=0?

(a) Factor will be (x-1)  x = 1 , -1+2i and -1-2i

(b) Solution of the equation will be                    

Step-by-step explanation:

We have given that 1 is the zero of the polynomial

(a) As x is zero of the polynomial so (x-1) will completely divide the polynomial

So

Now can be factorized as

So the linear factor of polynomial   will be

(x-1)

(b) Solution of the equation will be x = 1 , -1+2i and -1-2i

42.4

step-by-step explanation:

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