At 8: 00 am the smiths left a camp ground, driving at 48 mi/h. at 8: 20 am the garcia's left the same campground and followed the same route, driving at 60 mi/h. at what time did they overtake the smiths

9:40 am

Step-by-step explanation:

Let time taken from when Smith left compound to when Garcia overtakes Smith's car be represented by y

After y hours, Smith has covered 48*y=48y miles

Similarly, due to a difference of 20 minutes which is 20/60=1/3 hours, Garcia moves a distance of

60(y-1/3)

Equating both distances to be the same

60y-20=48y

12y=20

y=20/12=5/3 hours

Converted to minutes

5/3*60=100 minutes= 1 hr 40 mins

Therefore, adding 100 minutes to to starting time of Smith

8:00+1:40=9:40 am

The time that Garcia overtakes Smith is 9:40am

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)