Astraight line passed through p(-4,8) and q(0-2). find the equation of the perpendicular
bisector of the line pq

y = 2/5x + 11/5

Step-by-step explanation:

midpoint:

P(-4 , 8)

Q(0 , -2)

[(-4+0)/2 , (8-2)/2]

=(-4/2 , 6/2)

=(-2 , 3)

gradient:

m = (8+2)/(-4-0)

= 10/(-4)

= -5/2

= 2/5 (opp. of reciprocal)

equation:

y = mx + c

y = 2/5x + c

3 = 2/5(-2) + c (using coordinate of midpoint)

c = 3 + (-4/5)

= 11/5

y = 2/5x + 11/5

(Correct me if i am wrong)

answer: plz give a pic and answer choices so i can answer!

step-by-step explanation: