Las cruces, nm, is about 600 mi from dallas, tx. one plane flies from
dallas to las cruces in 1 hr 12 min. and another plane with the same
air speed flies from las cruces to dallas in 1 hr 30 min. find the air
speed of the planes and the speed of the wind.

The air speed of the plane is 450 mph and that of the wind is 50 mph.

Step-by-step explanation:

Let the speed of the plane is u and that of wind is v.

Therefore, with (u + v) speed the plane goes from Dallas to Las Cruces, i.e. 600 miles in 1 hr and 12 minutes i.e. 1.2 hours.

So, .......... (1)

And with (u - v) speed the plane goes from Las Cruces to Dallas in 1 hour and 30 minutes i.e. 1.5 hours.

So, ......... (2)

Solving equation (1) and equation (2), we get 2u = 900, ⇒ u = 450 miles per hour.

Now, from equation (1), we get, v = 500 - 450 = 50 miles per hour.

So, the airspeed of the plane is 450 mph and that of the wind is 50 mph. (Answer)

none of the above.

for one of the equations to be used in the process, there has to be a term in the equation since squared is .

since there is only a term in the first equation, we cannot derive a from completing the square.

solving with completing the square

idk this answer sorry cant on this one.

step-by-step explanation: