1. find three consecutive integers such that the sum of the first and twice the third
integer is 93 more than the second integer

Step-by-step explanation:

Let (x), (x+1), and (x+2) be the three consecutive integers.

Put the words into expressions

Sum of the 3rd and twice the 3rd:  (x)+2(x+2)

93 more than the second integer: 93+(x+1)

Now you can set up the equation and solve:

(x)+2(x+2)=93+(x+1)

Distribute and combine like terms

x+2x+4=94+x

3x+4=94+x

2x=90

x=45

So the 3 consecutive integers are 45, 46, 47.

Plug back in to check.

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.