Enter the enter the first four terms of the sequence defined by the given rule assume that the domain of each function is the set of whole numbers greater than f(1) =4, f(n)= (-5) •f(n-1)+11 the first 4 terms of the sequences are?

The first four terms of the sequence are 4, -9. 56 and -269

Given the sequence defined by the given rule

If the first term f(1) = 4.

Get the second term;

f(2) = -5f(2-1) + 11

f(2) = -5f(1) + 11

f(2) = -5(4) + 11

f(2) = -20 + 11

f(2) = -9

Get the third term;

f(3) = -5f(3-1) + 11

f(3) = -5f(2) + 11

f(3) = -5(-9) + 11

f(3) = 45 + 11

f(3) = 56

Get the fourth term;

f(4) = -5f(4-1) + 11

f(4) = -5f(3) + 11

f(4) = -5(56) + 11

f(4) = -280 + 11

f(4) = -269

Hence the first four terms of the sequence are 4, -9. 56 and -269

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  {1, -9, 56, -269}

Step-by-step explanation:

Evaluate the rule for n=2, 3, and 4 in sequence.

For n=2

  f(2) = (-5)f(1) +11 = (-5)(4) +11 = -9

  f(3) = (-5)f(2) +11 = (-5)(-9) +11 = 56

  f(4) = (-5)f(3) +11 = (-5)(56) +11 = -269

The first four terms of the sequence are {1, -9, 56, -269}.

distance covered by pamela in 9 l of fuel = 99km

let us apply unitary method here.

distance covered by pamela in 1 l of fuel =99/9 =11 km

now let us find distance covered by pamela if she has 12 l of fuel.

distance covered in 12 l = distance covered in 1 l of fuel * 12

we know that distance covered by here in 1 l is 11 km.

so distance covered in 12 l of fuel = 11*12 = 132 km.

answer:

3 bags of apples and 2 bags of oranges.

step-by-step explanation: