In a cricket match, a batsman hits a boundary 6 times out of 30 balls he plays. find the probability that he did not hit a boundary.

The probability of NOT hitting a boundary is (4/5).

Step-by-step explanation:

Let E: Be the event of hitting a boundary

now, Probability of any event E =  

Here, number of favorable outcomes = 6

So, P(E)  =

⇒Probability of hitting a six is 1/5

Now, P(E)  + P(not E)  = 1

So, P(not hitting a boundary ) = 1  -  P(hitting a boundary)

= 1 - (1/5)  = 4/5

Hence, the probability of NOT hitting a boundary is (4/5).

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

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step-by-step explanation: