Jessica had a bag of candies. she gave 1/8 of her candies to judy. then jessica gave 3/7 of the candies she had left to reggie. then she lost 75% of what she had left. after all this, jessica only had 4 candies left. how many candies did jessica have at the beginning? pls

Jessica had 32 candies at the beginning.

Step-by-step explanation:

Let the number of candies Jessica had at the beginning be .

Candies gives to Judy = .

Now, candies left with Jessica is .

Candies given to Reggie is of .

∴ Candies with Reggie is .

Candies left with Jessica after giving to Reggie = .

Now, Jessica lost 75% of what she had left. So, 75% of .

∴ Candies lost =

Now, candies left with Jessica = .

As per question,

Candies left with Jessica at last is 4. So,

Hence, Jessica had 32 candies at the beginning.

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)