14.
for exercises 7 through 25, assume that the sample is taken
from a large population and the correction factor can be
ignored. on no 2000 o algo
7. life of smoke detectors the average lifetime of smoke
detectors that a company manufactures is 5 years, or 60
months, and the standard deviation is 8 months. find the
probability that a random sample of 30 smoke detectors
will have a mean lifetime between 58 and 63 months.

0.8945

Step-by-step explanation:

The average life of smokers, is 60 months

Standard deviation is 8 months

Random sample, n is 30 smoke detectors

=

=

= P(-1.37 < Z < 2.05)

= P(Z < 2.05) - P(Z < -1.37)  Then from the standard tables, the Z values are 0.9798 for Z=2.05 and 0.0853 for Z=-1.37

= 0.9798 - 0.0853

= 0.8945

Therefore, the probability that a random sample of 30 smoke detectors will have a lifetime between 58 months and 63 months is 0.8945

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

substitute,

circle 1 = 5

circle 2 = 20

circle 3 = 44

in this case no matter how you add, you will always get a perfect square..

hence proved

happy to

pls mark as brainliest