The sum of three consecutive numbers is 144. find the numbers

47, 48, 49

Step-by-step explanation:

Consecutive numbers have a difference of 1 between them.

let n be the first number then n + 1 and n + 2 are the next 2 numbers, thus

n + n + 1 + n + 2 = 144 ← sum of 3 consecutive numbers, that is

3n + 3 = 144 ( subtract 3 from both sides )

3n = 141 ( divide both sides by 3 )

n = 47

Thus the 3 numbers are 47, 48 and 49

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

answer:   y=2x-3

step-by-step explanation: