Acrab crawls 7ft below sea level. directly above the crab a bird flies 15 ft above sea level what is the distance between the crab and the bird

The distance between the crab and the bird is 22 ft.

The crab is below sea level and the bird is above sea level.

Relative to sea level therefore, the crab is -7 ft to sea level.

The bird is +15 ft to sea level.

The distance between the crab and the bird is:

= Distance of bird relative to sea level - Distance of crab relative to sea level

= 15 - (-7)

= 15 + 7

= 22 ft

In conclusion, the distance between the crab and the bird is 22 ft.

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the answer is b.

step-by-step explanation:

identity property is where 0+whatever number=whatever number. basically 0+ a number.

the red lines denote the population of the bacteria after 35 hours. that would be 2,409.24. the y-intercept is the blue line which is 800 because that is the starting point. the equation used to make the graph is 800(1.032)^h, where h is the number of hours.

step-by-step explanation: