Which restriction is appropriate for the variable?
3y^2 - 3y/y-1
a. no restrictions are...
Mathematics, 01.09.2019 23:30 bapefer498
Which restriction is appropriate for the variable?
3y^2 - 3y/y-1
a. no restrictions are needed
b. y= -1
c. y =1
d. y = 3 <
Answers: 1
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