The third equation: ![y+2=-3(x-1)](/tpl/images/0347/2235/71769.png)
Step-by-step explanation:
The two points on the line are
and
.
Slope of the line passing through two points
and
is given as:
![m=(y_{2} -y_{1})/ (x_{2} -x_{1})](/tpl/images/0347/2235/b11e4.png)
Here,
and
are
and
.
Therefore, slope is equal to, ![m=(-2-4 )/ (1-(-1)](/tpl/images/0347/2235/b033a.png)
![m=-6/2](/tpl/images/0347/2235/da129.png)
Now, equation of a straight line with slope m and points
and
is given as:
![y-y_{1}=m(x-x_{1})\\y-y_{2}=m(x-x_{2})](/tpl/images/0347/2235/316b1.png)
Now, if we use the 2nd form, then
.
So, the equation is given as :
![y-(-2)=-3(x-1)\\y+2=-3(x-1)](/tpl/images/0347/2235/c5ec0.png)