Asurvey by the pew research center asked a random sample of 2142 u. s. adults and a random sample of 1055 college presidents how they would "rate the job the higher education system is doing in providing value for the money spent by students and their families." their choices were: excellent, good, only fair, or poor. 5% the u. s. adults and 17% of the college presidents provided a rating of "excellent." calculate the standard error of the difference in sample proportions (for adults minus presidents) based on this data. round your answer to 4 decimal places

Finding each variance and then applying the standard error, it is found that the standard error of the difference in sample proportions is of 0.0125.

For a proportion p in a sample of size n, the variances is given by:

The standard error of the difference of two sample proportions is the square root of the sum of the variances.

Sample of adults:

The variance is:

Sample of presidents:

The variance is:

Then, the standard error is:

The standard error is of 0.0125.

A similar problem is given at link

0.0125

Step-by-step explanation:

Given :  A survey by the Pew Research Center asked a random sample of 2142 U.S. adults and a random sample of 1055 college presidents how they would "rate the job the higher education system is doing in providing value for the money.

5% the U.S. adults and 17% of the college presidents provided a rating of "Excellent."

i.e.

,

The standard error of the difference in sample proportions  :-

Hence, the standard error of the difference in sample proportion = 0.0125

the first one is x^2+2x+2

the second one is x^2+4

the last one is x^2-4x+8

answer: 1/6

six accounts equally distributed