Arectangular window has a length of 81.47 cm and a width of 34.2 cm. what is the least precise measurement of the perimeter of the window? a 231.4 cm b 231.34 cm c 231.3 cm d 231 cm

In our case the least precise is the one with no decimal units, in our case 231 cm

Step-by-step explanation:

Perimeter=2(L+w)

where;

L=length=81.47 cm

W=width=34.2 cm

Replacing;

Perimeter=2(81.47+34.2)=231.34 cm

The most precise is the one with the highest decimal units, for example 231.34 in our case the least precise is the one with no decimal units, in our case 231

answer: (-6,3)

step-by-step explanation: