Knightmare give an algorithm to find the number of ways you can place knights on an n by m (m < n) chessboard such that no two knights can attack each other (there can be any number of knights on the board, including zero knights). clearly describe your algorithm and prove its correctness. the runtime should be o(23mm · n).

congruent segments

step-by-step explanation:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

no solution

step-by-step explanation:

there is not enough information in the problem to solve.

i don't see any

step-by-step explanation: