Want brainliest? come answer this then : d
the perimeter, p, of a rectangle is the sum of twice the length and twice the width.
select all that apply
btw (x is one of the sides and a rectangle can have 4 equal sides like a square)

p = 2(l+w) units
p = 2(5)+2(9) units
p = 4x units
p = (l+l)+(w+w) units
p = 2(x+3) units

= 1500 × 5/100

Step-by-step explanation:

Diagonal Formula. ... Any square that has two diagonals are equal in length to each other. Diagonal Formula is used to calculate the polygon diagonals. Diagonals are a line joining two nonadjacent vertices of a polygon i.e. a diagonal joins two vertices of a polygon excluding the edges of the figure. SO

Example 1: Rectangle has the length 13 cm and width 8 cm. solve for perimeter of rectangle.

Solution:

Given that:

Length (l) = 13 cm

Width (w) = 8 cm

Perimeter of the rectangle = 2(l + w) units

P = 2(13 + 8)

P = 2 (21)

P = 42

Thus, the perimeter of the rectangle is 42 cm.

Example 2: If a rectangle's length is 2x + 1 and its width is 2x – 1. If its area is 15 cm2, what are the rectangle's dimensions and what is its perimeter?

Solution:

We know that the dimensions of the rectangle in terms of x:

l = 2x + 1

w = 2x – 1

Since the area of a rectangle is given by:

A = l * w

We can substitute the expressions for length and width into the equation for area in order to determine the value of x.

A = l * w

15 = (2x + 1) (2x -1)

15 = 4x2 – 1

16 = 4x2

x = ±2

Note that the value of x must be positive and therefore in our case, the value of x is 2. And now we have:

l = 5 cm

w = 3 cm

Therefore, the dimensions are 5cm and 3cm.

Now, substituting these values in the formula for perimeter, we will get

P = 2l + 2w

P = 2(5)+2(3)

P = 10+6

P = 16 cm

Example 3: Find the area and the perimeter of a rectangle whose length is 24 m and width is 12m?

Solution:

Given that:

length = L = 24m

width = W = 12m

Area of a rectangle:

A = L × W

A = 24 × 12

A = 188 m2

Perimeter of a rectangle:

P = 2L + 2W

P = 2(24) + 2(12)

P = 48 + 24

P = 72 m

Example 4: Find the area and perimeter of a rectangle whose breadth is 4 cm and the height 3 cm.

Solution:

Area = b×h = 4×3 = 12 cm2.

Perimeter = 2(b) + 2(h) = 2(4) + 2(3) = 8 + 6 = 14.

Example 5: Calculate the perimeter of the rectangle whose length is 18cm and breadth 7cm

Solution:

Given that:

L = 18 cm

B = 7 cm

Perimeter of rectangle = 2(length + breadth)

P = 2 (L + B)

P = 2 (18 + 7)

P = 50 cm

Example 6: Find the perimeter of rectangle whose length is 6 inches and width is 4 inches.

Solution:

P = 2(L + B)

P = 2(6 + 4)

P = 20 in

Example 7: A boy walks 5 times around a park. If the size of the park is 100m by 50m, find the distance the boy has walked. If he walks 100m in 5 minutes, how long will it take for him in total?

Solution:

Given that:

Length = L = 100m

Width = W = 50m

Rounds = 5

Time per 100m = 5minutes.

Perimeter of the park:

P = 2 L + 2 W.

P = 2 × 100 + 2 × 50

P = 200 + 100

P = 300 m

Total distance walked = 5 × Perimeter of the park.

= 5 × 300

= 1500 meters

the two may have that, even a breakdown is probably offered

ok thats very interesting