What is the length of side bd in the triangle above?

BD = 14

Step-by-step explanation:

Using Pythagoras' identity on Δ's ADC and ABC

The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, thus

BC² + 12² = 15²

BC² + 144 = 225 ( subtract 144 from both sides )

BC² = 81 ( take the square root of both sides )

BC = = 9

and

DC² + 12² = 13²

DC² + 144 = 169 ( subtract 144 from both sides )

DC² = 25 ( take the square root of both sides )

DC = = 5

Hence

BD = BC + DC = 9 + 5 = 14

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

12

step-by-step explanation:

a triangle's   full angle is 180 degrees so 180 - 156 = 24. 24/2=12