Explain why numbers with a 5 in the ones place are not prime numbers.

Because it's divisible by 5 even though 5 is a prime number

In order for a number to be a prime number, it must only be divisible by 1 and itself. Just like any number that is even can be divisible by 2, any number that ends in 0 or 5 can be divisible by 5. So that is why a number that ends in 5 is not prime, because it has another factor other than 1 and itself, and that would be 5. Hope this helped! :D

50 % is the answer !

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12