Aline passes through the points (2-2) and (-6. 2). the point (a.-4) is also on the line. what is the value of a?

a = 6 is the desired value.

Step-by-step explanation:

Let two points be A and B , where A = (2,-2) and B = (-6,2)

Now, slope of the line AB  

or,

So, the slope m = -(1/2)

Now the general form of the equation is given by

y - y0 = m (x-x0) : where (x0, y0) is any point on the line of the equation.

So, here let (x0,y0) = (2, -2) and m  = -1/2

The equation becomes :  y -(-2) = (-1/2)(x-2)

or, x + 2y = -2 ia the formed equation.

Now here substiture thepoint (a, -4)

we get:  a + 2(-4) = -2

or, a = -2 + 8 = 6

or a = 6 is the desired value.

56.6

step-by-step explanation:

the ratio of the perimeters is equal to the scale.

the ratio of the areas is equal to the square of the scale.

34 / 20 = k

a / 19.6 = k²

substituting:

a / 19.6 = (34 / 20)²

a = 19.6 (34 / 20)²

a ≈ 56.6

i think it would be 42cm