Astress analysis was conducted on random samples of epoxy-bonded joints from two species of wood. a random sample of 120 joints from species a had a mean shear stress of 1250 psi and a standard deviation of 350 psi, and a random sample of 90 joints from species b had a mean shear stress of1400 psi and a standard deviation of 250 psi. find a 98% confidence interval for the difference in mean shear stress between the two species

Our required 98% confidence interval would be (53.51,246.49).

Step-by-step explanation:

Since we have given that

Sample of joints from species A = 120

Mean of shear stress = 1250 psi

Standard deviation = 350 psi

Sample of joints from species B = 90

Mean = 1400 psi

Standard deviation = 250 psi

98% confidence interval

α = 100 -98  = 2%

98% confidence interval would be

Hence, our required 98% confidence interval would be (53.51,246.49).

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation:

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step-by-step explanation: