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Mathematics, 23.10.2019 06:00 bri9263

Solve f(x)=3(2x+1)^2-5=142 by using the inverse function f^-1(x)=1/2[โˆšx+5/3 -1]

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Solve f(x)=3(2x+1)^2-5=142 by using the inverse function f^-1(x)=1/2[โˆšx+5/3 -1]...
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