The probability that the san jose sharks will win any given game is 0.3694 based on a 13-year win history of 382 wins out of 1,034 games played (as of a certain date). an upcoming monthly schedule contains 12 games. what is the expected number of wins for the that upcoming month? let x = number of games won in november 2005. (round your answer to two decimal places.)

4.43

Step-by-step explanation:

Given :The probability that the San Jose Sharks will win any given game is 0.3694 based on a 13-year win history of 382 wins out of 1,034 games played

To Find : What is the expected number of wins for the that upcoming month?

Solution :

The probability that the San Jose Sharks will win is 0.3694

Let X = number of games won

Total no. of games = 12

We are supposed to find the expected number of wins for the that upcoming month

So, expected number of wins = E(X)=XP(X)=

Hence the expected number of wins for the that upcoming month is 4.43

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40

can you make your screen more see able?

then i might be able to .