Solve for x in the equation x^2+2x+1=17

x= (-1+ √17) or (-1-√17)

Step-by-step explanation:

In this question, we have to solve for x from the given equation x² +2x+1 =17

Now, the equation can be rearranged to x² +2x -16 =0.

Here we can not apply the process of factorization to get the value of x.

Hence, we will use the Shridhar Acharya formula to solve the value of x.

{This formula gives, if ax² +bx +c =0 then, the value of x can be solved as

x=[-b±√(b²-4ac)]/2a }

Hence, in this case, the solution for x will be

x=

⇒ x=

⇒ x= (-1+ √17) or (-1-√17) (Answer)

12*c

step-by-step explanation:

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation: