Calculate the probability for the following situation, then select the correct you are tossing a coin, then rolling a die, then drawing a card from a deck of cards. what is the probability that you will get: a head and an odd number on the die and a card less than 10 (assume the ace is equal to 1) from the deck?

9/52

Step-by-step explanation:

This is a case of multiple events happening at the same time, so we need to find the probability of each event and multiply them together.

Formula for finding probability is as follow:

P(E) = Number of Favorable Outcomes / Number of Total Outcomes

Probability of Heads:

Favorable Outcomes = 1 (Heads)

Total Outcomes = 2 (Heads, Tails)

P(H) = 1/2

Probability of Odd Number:

*Assuming six sided unbiased die

Favorable Outcome = 3 (1, 3, 5)

Total Outcomes = 6 (1, 2, 3, 4, 5)

P(Odd) = 3/6 or 1/2

Probability of Card Less than 10:

*Assuming a deck of  52 cards

Favorable Outcomes = 36 (Ace, 2, 3, 4, 5, 6, 7, 8, 9  times 4)

Total Outcomes = 52 (Ace, 2, 3 ,4 ,5 ,6 ,7 ,8 ,9, 10, J, Q, K times 4)

P(<10) = 36/52 or 9/13

Probability of All Events Occurring:

P(E) = P(H) x P(Odd) x P(<10)

P(E) = 1/2 x 1/2 x 9/13

P(E) = 9/52   Answer

3

step-by-step explanation:

location: point 0

step-by-step explanation:

well, -8 to 10 on a number line is 18 spaces.

1/9 of 18 is 2.

so, 4/9 of 18 must be 8.

8 spaces from -8 (a) is 0.

so, 4/9 of the way from -8 to 10 is 0!