Start with the logistic equation dx dt = kx(m x). suppose we modify our harvesting. that is we will only harvest an amount proportional to current population. in other words, we harvest hx per unit of time for some h > 0 (similar to earlier example with h replaced with hx). a) construct the di erential equation. b) show that if km > h, then the equation is still logistic. c) what happens when km < h?

step-by-step explanation:

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step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2