In the figure, ∠1 ≅ ∠2, ∠3 ≅ ∠4, and . you can justify the conclusion that ∆tks ≅ ∆tlr by the
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Mathematics, 22.10.2019 05:50 brianamarialove15
In the figure, ∠1 ≅ ∠2, ∠3 ≅ ∠4, and . you can justify the conclusion that ∆tks ≅ ∆tlr by the
sss postulate.
aas theorem.
sas postulate.
asa postulate.
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