118. sami opens an account and deposits $100 into it at the end of each month. the account earns 2% per year compounded monthly. let sn denote the amount of money in her account at the end of n months (just after she makes a deposit). for example, s1 = 100 and s2 = 100(1 + 0.02 /12)+100
d. when will sami have at least $5,000 in her account? show work to support your answer.

The answer = 48.07 approx.

Step-by-step explanation:

b)

5000 = 100 (1 -( 1+ \frac{0.02}{12} )^n) / 1 - ( 1 + \frac{0.02}{12})

50 (- \frac{0.02}{12}) = 1 - ( 1 + \frac{0.02}{12} )^n

\frac{13}{12} = 1 + \frac{0.02}{12})^n

n = log(\frac{13}{12}) = log(1 + \frac{0.02}{12})^n

n = log(\frac{13}{12}) \ log(1 + \frac{0.02}{12})^n

The answer = 48.07 approx.

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

an

y = 6x -3y -12

y +3y +12 = 6x

=> . x = { 2y / 3 +2 } this is equation of line in terms of x

=> . if line meets the x-axis the co-ordinates of meeting point would be ( x , 0 )

=> . x = 2 ( 0 ) / 3 + 2

=> . x = 2

so, the point is ( 2 , 0 )