Find all solutions to the following equation. if there are any extraneous solutions, identify them and explain why they are extraneous.(7/b+3)+(5/b-3)=(10b/b²- 9)

b = 3, which is an extraneous solution because if we replace b = 3 in the equation, we must be 5/0 and 30/0, and there is division by 0.

Step-by-step explanation:

The minus common multiply must be (b-3)*(b+3) = b² - 9

7b - 21 + 5b + 15 = 10b

2b = 6

b = 3

Which is an extraneous solution because if we replace b = 3 in the equation, we must be 5/0 and 30/0, and there is division by 0. So this solution is invalid.

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step-by-step explanation:

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