Find the values of t so that the tangent line to the given curve is contains the given point? given r(t)=2ti+t^2j-t^2k at point (0,-4,4)

t = -2,2

Step-by-step explanation:

The curve equation,

Let at t=a tangent to the curve.

Equation of tangent:  

L(k) = r(a) + k r'(a)

Put t=a

Equation of tangent:

Tangent passing through (0,-4,4)

Therefore,

2a + 2k = 0   ⇒  k = -a

At t = -2,2  tangent line to the curve passing through (0,-4,4)

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)

47.28 or 47.2857143

step-by-step explanation:

you just divide 331 by 7 and you get that answer. ( i think so tho)