What is the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the
point (2,5)?
y + 5 = x + 2
y-2 = x-5
y-5=-(x - 2)
y + 2 = -(x + 5)

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmmm what's the slope of that line above anyway,

so we're really looking for the equation of a line whose slope is -1 and runs through (2,5)

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.