Graph this compound inequality: 2 < -8 or > 3
-10-9-8-7-6-5-4-3-2-1 0
1 2
3
4 5 6
7 8 9 10

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~

answer: translate the circles so they share a common center point and dilate circle y by a scale factor of 3.