Part1
pic is for
i i
i i
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describe the error in the way the calculation of the slope of the two points is set up and/or solved. be specific. do not just state what the slope should be. describe the error.

part2

use the same two points from the error analysis question above and show how to calculate the slope correctly. then, use the correct slope and one of the points to write the equation in point-slope form of the line. show all work!
part 3

describe in detail how you would graph the line y = -3x + 2 on a coordinate plane. be specific. (3 points)

Part 1.

The slope is found by the change in Y over the change in X.

In the picture they are finding the difference between the X and Y of each point. They have x1 - y1 over x2-y2, when it should be y2-y1 / x2 - x1.

Part 2:

Slope = Change in Y over change in X:

(4 - 6) / (0 - -2) = -2 / 2 = -1

Slope = -1

Using the point (0,4) tells you the Y-intercept, which is the Y value when x is 0. The Y intercept is added to the slope when writing the equation of a line in point slope form.

The equation is y = -x +4

Part 3:

Find two points on the line by replacing X with 0 and solving for Y and then replace Y with 0 and solve for X. This gives you the X and Y intercepts. Once you have those two points, put them on a graph and then draw a straight line through both dots.

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.