Sin^2 x - 2 sin x = 0

find all solutions to the equation in the interval

Let . The equation becomes

So, the solutions are

Substitute back , we have

Since the sine function is bounded between -1 and 1, it can never equal 2. So, the only possible solution is

Depending on the interval you're interested in (you didn't write it!) select the solution(s) that applies(apply)

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step-by-step explanation: vsfdvsfvd