An auditorium has 55 rows of seats. the first rows contains 100 seats as you move the rear of the auditorium each row has four more seats than the previous row how many seats are in the row 37 how many seats are in the auditorium

i need and show work.

true? is that what you're asking or do you mean something else?

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3

answer:

your answer is: c. 196 7/8 in^3.

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step-by-step explanation: