Keith is a drummer who purchases his drumsticks online. when practicing with the newest pair, he notices they feel heavier than usual. when he weighs one of the sticks, he finds that it is 2.23 oz. the manufacturer's website states that the average weight of each stick is 1.85 oz with a standard deviation of 0.18 oz. assume that the weight of the drumsticks is normally distributed.

what is the probability of the stick's weight being 2.23 oz or greater? give your answer as a percentage precise to at least two decimal places.

0.0174

Step-by-step explanation:

Given :

Let x be the random variable that represents  the weight of the drumsticks.

We assume that the weight of the drumsticks is normally distributed.

Now, the z-score for x=2.23 ,

Using z-value table , we have

P-value =P(x≥2.23)=P(z≥2.11)=1-P(z<2.11)=1-0.9825708

=0.0174292≈0.0174 [Rounded nearest 4 decimal places]

Hence, the  probability of the stick's weight being 2.23 oz or greater = 0.0174

answer: asdfghjkl,mnbv

step-by-step explanation:

required rate of return = 0.166 = 16.6%

step-by-step explanation:

under the capital asset pricing model (capm), the required or expected rate of return for a particular security or asset is given using the formula:

required rate of return = risk-free rate + beta*(market risk premium)

we are given that;

risk-free rate = 4% = 0.04

beta = 1.4

market risk premium = 9% = 0.09

we simply plug these values into the above formula;

required rate of return = 0.04 + 1.4*(0.09)

required rate of return = 0.04 + 0.126

required rate of return = 0.166 = 16.6%