Adistribution of scores is approximately normal with a mean of 78 and a standard deviation of 8.6. which of the following equations can be used to find the score x above which 33 percent of the scores fall?
(a) 0.44=1.78
(b) 0.67= 78
(c) 0.33= -78
(d) 0.44=1.78
(e) 0.67-8.68

The correct answer is (D)

Step-by-step explanation:

If we check the value in the Normal Distribution table, the x score that falls above 33% is given by:

P(z>x)=0.33

1 - P(z≤x)=0.33

1 - 0.33=P(z≤x)

0.67=P(z≤x)⇒ z=0.44

Also

z=(x-μ)/σ

where:

μ: mean of the distribution

σ: standard deviation of the distribution

Hence,

0.44=(x-78)/8.6

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.