According to the national institute of allergy and infectious diseases, approximately 7% of american children 4 years of age or under have a food allergy. a day care has capacity for 8 children in that age range. assume that the children attending the daycare are independent. let the random variable x
be the number of children in this day care who have a food allergy. the probability p(x < 2) is

89.65%

Step-by-step explanation:

This can be modeled with a binomial distribution with probability of “success” (having a food allergy) equals 7% (0.07) and the probability of “failure” (not having food allergy) equals 0.93 in 8 “trials” (8 children).

P(X < 2) = P(X = 0) + P(X = 1) =

we can compute this either by hand or computer assisted and we get our probability equals

0.8965 0r 89.65%

17 1/3

step-by-step explanation:

  the correct choice is marked

step-by-step explanation:

the first two graphs show multiple turning points. the last graphs matches the description in every detail.