![\begin{cases}\dfrac{2\sqrt[3]{u}}{u-v}+\dfrac{2\sqrt[3]{u}}{u+v}=\dfrac{81}{182}\\\\\dfrac{2\sqrt[3]{v}}{u-v}-\dfrac{2\sqrt[3]{v}}{u+v}=\dfrac1{182}\end{cases}](/tpl/images/0331/9121/09ff0.png)
![\begin{cases}\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81}{182}\\\\\dfrac{4\sqrt[3]{v^4}}{u^2-v^2}=\dfrac1{182}\end{cases}](/tpl/images/0331/9121/3e511.png)
![\dfrac{4\sqrt[3]{u^4}}{u^2-v^2}=\dfrac{81\times4\sqrt[3]{v^4}}{u^2-v^2}](/tpl/images/0331/9121/7ef09.png)
![\implies\sqrt[3]{\left(\dfrac uv\right)^4}=81](/tpl/images/0331/9121/83a5f.png)
![\dfrac{4\sqrt[3]{v^4}}{(\pm27v)^2-v^2}=\dfrac1{182}\implies\dfrac1{v^2}=1\implies v=\pm1](/tpl/images/0331/9121/6b55c.png)
Solve this system of equations
[tex]\left\{\begin{matrix}\frac{\ sqrt[3]{2x+y}}{y}+\frac{...
Answers: 1
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