Mathematics, 18.10.2019 17:10 reaperdraws

Suppose you just purchased a digital music player and have put 15 tracks on it. after listening to them you decide that you like 3 of the songs. with the random feature on your player, each of the 15 songs is played once in random order. find the probability that among the first two songs played

(a) you like both of them. would this be unusual?

(b) you like neither of them.

(c) you like exactly one of them.

(d) redo () if a song can be replayed before all

15 songs are played.

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Answer from: michyfbg

This is about probability and combinations.

a) 0.0286

b) 0.6286

c) 0.3429

d) 0.04, 0.64, 0.32

Total number of songs in music player = 15 tracksNumber of songs you like = 3 songsNumber of songs you don't like = 15 - 3 = 12A) Probability you will like the first one = 3/15

After the first one, there are 14 left and 2 you may like. Probability you will like the second one = 2/14. Thus;

P(you like both of the first two played) = 3/15 × 2/14

P(you like both of the first two played) = 0.0286

B) Probability you will not like the first one = 12/15

After the first one, there are 14 left and 11 you may not like. Probability you will not like the second one = 11/14. Thus;

P(you like both of the first two played) = 12/15 × 11/14

P(you like neither of the first two played) = 0.6286

C) Probability you like exactly one of them means you may like the first and dislike the second or you may dislike the first and like the second. Thus, this probability is;

P(like exactly one of the first two) = (3/15 × 12/14) + (12/15 × 3/14)

P(like exactly one of the first two) = 0.3429

d) If a song is replayed before all, then;

a) P(you like neither of the first two played) = 3/15 × 3/15

P(you like neither of the first two played) = 0.04

b) P(you like neither of the first two played) = 12/15 × 12/15

P(you like neither of the first two played) = 0.64

c) P(like exactly one of the first two) = (3/15 × 12/15) + (12/15 × 3/15)

P(like exactly one of the first two) = 0.32

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Answer from: miracle96

Total songs = 15

Liked songs = 3

Un liked songs = 15-3=12

Find the probability that among the first two songs played

(a) You like both of them.

Probability that among the first two songs played you like both of them = $\frac{3}{15} \times \frac{2}{14} = 0.029$

(b) You like neither of them.

Probability that among the first two songs played you like neither of them = $\frac{12}{15} \times \frac{11}{14} = 0.629$

Probability that among the first two songs played you like exactly one of them = $\frac{3}{15} \times \frac{12}{14}+ \frac{12}{15} \times \frac{3}{14}= 0.343$

(d) Redo (a)-(c) if a song can be replayed before all

(a) You like both of them. Would this be unusual?

Probability that among the first two songs played you like both of them = $\frac{3}{15} \times \frac{3}{15} = 0.04$

(b) You like neither of them.

Probability that among the first two songs played you like neither of them = $\frac{12}{15} \times \frac{12}{15} = 0.64$

Probability that among the first two songs played you like exactly one of them = $\frac{3}{15} \times \frac{12}{15}+ \frac{12}{15} \times \frac{3}{15}= 0.32$

Answer from: Quest

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.

Answer from: Quest

$x=2\sqrt{10}$

step-by-step explanation:

this can be solved first with pythagorean theorem, which tells us to square both legs of the triangle and sum it. this will be equal to the square of the hypotenuse.

the hypotenuse is the side "opposite" the 90 degree angle, which is x.

so we can write using pythagorean theorem,

$6^2+2^2=x^2$

simplifying:

$6^2+2^2=x^2\\36+4=x^2\\40=x^2\\x=\sqrt{40}$

to further simplify this radical, we need to use the property $\sqrt{x*y}=\sqrt{x} \sqrt{y}$

thus

$x=\sqrt{40}\\ x=\sqrt{4}\sqrt{10} \\ x=2\sqrt{10}$

What is the value of x? leave your answer in simplest radical form.

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