Acone fits inside a square pyramid as shown. for every cross section, the ratio of the area of the circle to the area of the square is startfraction pi r squared over 4 r squared endfraction or startfraction pi over 4 endfraction.

a cone is inside of a pyramid with a square base. the cone has a height of h and a radius of r. the pyramid has a base length of 2 r.

since the area of the circle is startfraction pi over 4 endfraction the area of the square, the volume of the cone equals

a. startfraction pi over 4 endfraction the volume of the pyramid or startfraction pi over 4 endfractionstartfraction pi over 4 endfraction (startfraction (2 r) (h) over 3 endfraction) or one-sixthπrh.

b. startfraction pi over 4 endfraction the volume of the pyramid or startfraction pi over 4 endfractionstartfraction pi over 4 endfraction (startfraction (2 r) squared (h) over 3 endfraction) or one-thirdπr2h.

c. startfraction pi over 2 endfraction the volume of the pyramid or startfraction pi over 2 endfraction or two-thirdsπr2h.

d. startfraction pi over 2 endfraction the volume of the pyramid or startfraction pi over 4 endfraction or one-thirdπr2h.

The focus of parabola is (-4, -5), and its directrix is y= -1. fill in the missing terms and signs in parabolas equation in standard form

Put the equation in slope intercept form by solving for y

In a test for esp (extrasensory perception), the experimenter looks at cards that are hidden from the subject. each card contains either a star, a circle, a wave, a cross or a square.(five shapes) as the experimenter looks at each of 20 cards in turn, the subject names the shape on the card. when the esp study described above discovers a subject whose performance appears to be better than guessing, the study continues at greater length. the experimenter looks at many cards bearing one of five shapes (star, square, circle, wave, and cross) in an order determined by random numbers. the subject cannot see the experimenter as he looks at each card in turn, in order to avoid any possible nonverbal clues. the answers of a subject who does not have esp should be independent observations, each with probability 1/5 of success. we record 1000 attempts. which of the following assumptions must be met in order to solve this problem? it's reasonable to assume normality 0.8(1000), 0.2(1000)%30 approximately normal 0.8(1000), 0.2(1000)% 10 approximately normal srs it is reasonable to assume the total number of cards is over 10,000 it is reasonable to assume the total number of cards is over 1000