What is an equation in point-slope form of the line that passes through the point (4, −1) and has slope 6?

y+1=6(x-4)

Step-by-step explanation:

In the question you are already given the information needed, so you don't have to really solve anything further. All you have to do is input it into the point-slope form equation y-y1=m(x-x1) from x1=4 y1=-1 and m=6, giving you y+1=6(x-4). If you're wondering, I got the + in y+1 because of the two negatives being together giving you a positive.

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.

see below

step-by-step explanation:

x+2> 6

subtract 2 from each side

x+2-2 > 6-2

x > 4

there is an open circle at 4 since is it is greater than and the line goes to the right