Acompany wants to installan underground storage tank that is in the shape of acylinder with both ends being in the shape of a hemisphere. the tank will have anoutside diameter of 20 feet and a total length of 50 feet (that is from the tip of one end ofthe hemisphere shape to the tip of the other hemisphere shape)lf the walls of the tankare 3 inches thick, what is the volume of the tank in cubic feet and how many gallons ofliquid can be contained in the tank (1 cubic foot 7.48 gallons)?

Wallsare 3 inches thick
diameter is 20 feet, find real diametter
legnth is 50 feet, find real legnth

minus 6 inches from each measurement since that is not included

20ft-6in=19.5ft
50ft-6n=49.5ft

we have a cylinder and a 2 hemispheres
2 hemispheres=1 sphere

Vcylinder=hpir^2
Vsphere=(4/3)pir^3

r=d/2
r=19.5/2=9.75
h=49.5

Vcylinder=49.5*pi*9.75^2=14783.058738886 ft^3
Vspere=(4/3)pi9.75^3=388419466778 ft^3
add them
Vcylinder+Vspher=14783.058738886+388419466778 ft^3=18665,478205664ft^3

V=18665,478205664 ft^3
times 7.48 to find gallons
Vingallons=139617.77697837 gallons

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )