Equation of the line slope with slope -3 and the passes through (2,-1)

The equation of the line with slope -3 and passes through (2,-1) is y = -3x + 5

Solution:

In the question it is given that the line passes through the point (2,-1) with slope (m) = -3. We have to find out the point slope form and slope intercept form of the equation.

We know the point - slope form of an equation is given by  

Substituting the values in the point slope form of the equation we get

(y-(-1)) = -3(x-2)

(y+1) = -3 (x-2) is the point slope form of given line

We know the slope intercept form of a line is given by  

y = mx +c  

Here y = -1 , x = 2 and m = -3

Substituting the values in slope intercept form equation we get

-1 = (-3)2 + c

⇒-1 = -6 + c

⇒-1+6 = c

c = 5

Thus the slope intercept form of equation is y = -3x+5

hello from mrbilldoesmath!

answer:   x^2 + y^2 = 1024

discussion:

the equation of a circle with center (h,k) and radius "r" is

(x-h)^2 + (y-k)^2 = r^2.

in our case

(x-0)^2 + (y-0) ^2 = 32^2 = 1024

you,

mrb