Xy is dilated by a scale factor of 1.3 with the origin as the center of dilation to create the image x'y'. if the slope and length of xy are m and l respectively, what is the slope of x'y'?

Hello,

Dilatations conserved parallelism

=> slope of X'Y'=m= slope of XY

Dilatations multiply length by the scale factor

==> |X'Y'|=1.3*|XY-=1.3*L

 The slope of line X'Y'= m

Step-by-step explanation:

Given: XY is dilated by a scale factor of 1.3 with the origin as the center of dilation to create the image X'Y'.

The slope and length of XY are m and l respectively.

Dilation is a transformation that forms similar shape, but with a different size such that the corresponding sides of image and original shape are parallel to each other.

As the slope of parallel line are equal .

⇒ The slope of XY and X'Y' are equal.

Hence, the slope of X'Y' is m.

Just tell koda to adjust the number of shapes himself.

D.